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A Scooter was bought at 42,000. Itsvalue depreciated at the rate of 8%annum. Find its value after one ycar.per |
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Answer» Ans :- Given: Principal (P) =₹ 42,000,Rate of Interest (R) = 8%, Time(n)=1 years Amount (A) =P(1-R/100)^n [Value depreciated] A= 42000(1-8/100)¹ A=42000(1-2/25) A= (42000×23)/25 A= 1680× 23 A= ₹ 38640 Hence, the value of the scooter after one year = ₹ 38640. |
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