1.

A Scooter was bought at 42,000. Itsvalue depreciated at the rate of 8%annum. Find its value after one ycar.per

Answer»

Ans :- Given:

Principal (P) =₹ 42,000,Rate of Interest (R) = 8%, Time(n)=1 years

Amount (A) =P(1-R/100)^n

[Value depreciated]

A= 42000(1-8/100)¹

A=42000(1-2/25)

A= (42000×23)/25

A= 1680× 23

A= ₹ 38640

Hence, the value of the scooter after one year = ₹ 38640.



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