A scooter can produce a maximum acceleration of 5ms^(-2). Its brakes can produce a maximum retardation of 10ms^(-2). The minimum time in which it can cover a distance of 1.5 km is?

A scooter can produce a maximum acceleration of 5ms^(-2). Its brakes c

1.	A scooter can produce a maximum acceleration of 5ms^(-2). Its brakes can produce a maximum retardation of 10ms^(-2). The minimum time in which it can cover a distance of 1.5 km is?
Answer» SOLUTION : If v is the maximum velocity attained, then during acceleration is between A, B `v^(2)-o^(2)=2xx5xxS_(1)impliesS_(1)=(v^(2))/(10)`, Also, during RETARDATION `o^(2)-v^(2)=2xx10xxS_(2)impliesS_(2)=(v^(2))/(20)` `S=S_(1)+S_(2)implies1500=(v^(2))/(10)+(v^(2))/(20)=(3v^(2))/(20)or` `v^(2)=(1500xx20)/(3)=10000 or v=100ms^(-1)` `v=alphat_(1)impliest_(1)=(100)/(5)=20SEC` `v=betat_(2)impliest_(2)=(100)/(10)=10sec` Total time `=20+10=30sec`.