1.

A scale of 1:25000 a rectangular plot of land ABCD has the following measurements-ab=12cm,bc=16cm find-a)the diagonal dist of the plot in km,b)the area of the plot in sq km

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Answers

Golda Ace

Solution:-

Given : AB = 12 cm, BC = 16 cm and AB is ⊥ to BC

Now, applying Pythagoras Theorem,

Hypotenuse² = Perpendicular² + Base²

⇒ AC² = AB² + BC²

⇒ AC² = 12² + 16²

⇒ AC² = 144 + 256

⇒ AC² = 400 

⇒ AC = √400

AC = 20 cm

There is a relation between Hypotenuse (AC) and CIRCUMRADIUS (r).

The hypotenuse is the diameter of the circle and, and its CENTER is exactly the midpoint of the hypotenuse.

So, Hypotenuse = 2r

Therefore,

r = hypotenuse/2

r = 20/2

Radius of the circle = 10 cm

Answer.


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