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A satellite revolves round a planet in an elliptical orbit. Its maximum and minimum distance from planet are 1.5xx10^(7) metre and 0.5xx10^(7) metre respectively. If the speed of the satellite at the farthest point is 5xx10^(3)m//s. Calculate the speed at the nearest point. |
Answer» Solution :The angular momentum of the satellite about the planet is CONSTANT. `thereforemv_(1)r_(1)=mv_(2)r_(2)` (or)`v_(1)r_(1)=v_(2)r_(2)` `therefore` Speed at nearest part `v_(1)=(v_(2)r_(2))/(r_1)=(5XX10^(3)xx1.5xx10^(7))/(0.5xx10^(7))` `therefore""v_(1)=1.5xx10^(4)m//s` |
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