A Satellite orbits the earth at a height of 400 km above the surface . How much energy must be expended to rocketthe satellite out of the gravititionalinfluence of earth? Mass of the satellite is 200 kg , mass of the earth = 6.0xx10^24 kg , radius of the earth =6.4xx10^6 m , G=6.67xx10^(-11) Nm^2 kg^(-2)

A Satellite orbits the earth at a height of 400 km above the surface .

1.	A Satellite orbits the earth at a height of 400 km above the surface . How much energy must be expended to rocketthe satellite out of the gravititionalinfluence of earth? Mass of the satellite is 200 kg , mass of the earth = 6.0xx10^24 kg , radius of the earth =6.4xx10^6 m , G=6.67xx10^(-11) Nm^2 kg^(-2)
Answer» Solution :Total ENERGY of orbiting satellite at a HEIGHT `h=(-GMm)/(2(R+h))` Energy expended to ROCKET the satellite out of the earth.s gravititional field = - (total energy of the satellite) `=(GMm)/(2(R+h))=((6.67xx10^(-11))XX(6xx10^24)xx200)/(2(6.4xx10^6+4xx10^5))=5.9xx10^9` J