A satellite is revolving round the earth in a circular orbit with a velocity of 8k/s. at a height where acceleration due to gravity is 8 m//s^2 . How many high is e satellite from the earth ( Take R = 6000km)

A satellite is revolving round the earth in a circular orbit with a ve

1.	A satellite is revolving round the earth in a circular orbit with a velocity of 8k/s. at a height where acceleration due to gravity is 8 m//s^2 . How many high is e satellite from the earth ( Take R = 6000km)
Answer» Solution :As centripetal acceleration equals to acceleration DUE to GRAVITY at that height , then `:.a=V^2/r=g_(h)impliesV^2/r=8=(64xx10^(6))/(R+h)=8` `implies R + h = 8 xx10^(6)` `h = 8 xx10^(6) - 6 xx10^(6)= 2 xx10^(6) m = 2000 KM `