1.

A satellite is revolving in circular orbit of radius r around the earth of mass M. Time of revolution of satellite is

Answer»

`Tprop(r^(5))/(GM)`
`T propsqrt((r^(3))/(GM))`
`T prop sqrt((r)/((GM^(2))/(3)))`
`T prop sqrt((r^(3))/((GM)/(4)))`

SOLUTION :The TIME PERIOD of revolution of satellite is given by
`rArr T=2pisqrt((r^(3))/(GM))rArr T=prop sqrt((r^(3))/(GM))`.


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