A satellite is a at height of 25, 600 km from the surface of the earth. If its orbital speed is 3.536 km/s find its time period. (Radius of the earth = 6400 km)

A satellite is a at height of 25, 600 km from the surface of the earth

1.	A satellite is a at height of 25, 600 km from the surface of the earth. If its orbital speed is 3.536 km/s find its time period. (Radius of the earth = 6400 km)
Answer» Solution :`R = 6400 KM = 6.4 xx 10^(6)m` `h = 25, 600 km = 25.6 xx 10^(6)m`, `v_(0) = 3.536 xx 10^(3) m//s` The time PERIOD `T = (2pi(R+h))/(V_(0)) = (2pi(256.6 xx 6.4)10^(6))/(3.536 xx 10^(3))` `= (2pi xx 32)/(3.536) xx 10^(3) = 56.870 s`