a sample of pure magnisium carbonate was found to contain 28.57% of magnisium 14.29% of calcium and 57.14% of oxygen .if law of constant composition is true what mass of magnisium ,carbon and oxygen should be present in 5g of magnisium carbonate

a sample of pure magnisium carbonate was found to contain 28.57% of ma

1.	a sample of pure magnisium carbonate was found to contain 28.57% of magnisium 14.29% of calcium and 57.14% of oxygen .if law of constant composition is true what mass of magnisium ,carbon and oxygen should be present in 5g of magnisium carbonate
Answer» that the statement of Law of Constant Proportion is known to you.Now, by Law of Constant Proportion, the PERCENTAGE of Each of the GIVEN elements(Mg, C and O) will be fixed in any given mass of MgCO3 (Magnesium Carbonate).Now,By Law of Constant Proportion, the masses of the element present in a given compound will be:= [(Mass Percentage of Element)/100] × Given Mass of CompoundFor Magnesium, it'll be= [28.57/100]×5= 1.42gFor Carbon, it'll be= [14.29/100]×5= 0.71gFor Oxygen, it'll be= [57.14/100]×5= 2.85gTo verify, we add them up, it gives4.98g, which is approximately equal to 5g (the given mass of the compound), which VERIFIES the law of constant proportion.