Saved Bookmarks
| 1. |
A sample of metal weights 210 grams in air 180 grams n water and 120 grams in an unknown liquid thenA. Metal of 3B. Metal is 7C. Liquid of 3D. Liquid is `(1)/(3)` |
|
Answer» Correct Answer - B::C Let the density of metal is p and density of liquid is `sigma`. If V is the volume of sample then according to problem `210 = Vrhog " "…….(i)` `180 = V(rho-1)g " "……(ii)` `120 = V(rho-sigma)g " "……..(iii)` By solving (i),(ii) and (iii) we get `rho = 7` and `sigma = 3`. |
|