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a sample of KClO3 on decomposition fielded for 448 ml of Oxygen gas at STP then the weight of KClO3 original you taken was |
Answer» ANSWER:-Oxygen = 448 ml 22400 =448 =0.02moles →2KCl+3O 2 POAC in Oxygen Atoms Oxygen in KClO3 oxygen in O2 KClO3) = 3 moles of O2 (=3×0.022× 122.5x) =0.06 x=0.03×122.5 x=3.675g Answer=3.675g |
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