1.

a sample of KClO3 on decomposition fielded for 448 ml of Oxygen gas at STP then the weight of KClO3 original you taken was

Answer»

ANSWER:-

Oxygen = 448 ml

MOLES produced =O2

22400 =448

=0.02moles

→2KCl+3O 2

POAC in Oxygen Atoms

Oxygen in KClO3 oxygen in O2

KClO3) = 3 moles of O2

(=3×0.022× 122.5x)

=0.06

x=0.03×122.5

x=3.675g

Answer=3.675g



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