A sample of HI (g) is placed in flask at a pressure of 0.2 atm. At equilibrium, the partial pressure of HI (g) is 0.04 atm. What is for the given equilibrium ?

A sample of HI (g) is placed in flask at a pressure of 0.2 atm. At equ

1.	A sample of HI (g) is placed in flask at a pressure of 0.2 atm. At equilibrium, the partial pressure of HI (g) is 0.04 atm. What is for the given equilibrium ?
Answer» EQUILIBRIUM constant calculated with the partial pressures of the gaseous reactants and products in an equilibrium reaction. The formula to CALCULATE Kp: Reaction equation: The equilibrium pressure of and is calculated by calculating the DECREASE in the pressures of HI (0.2 - 0.04 = 0.16 atm) As per the equation, 2 moles of HI dissociates to GIVE 1 mole of and 1 mole of .Hence, the equilibrium pressure of is and of is .INITIAL Pressure of HI: 0.2 atm Equilibrium Pressure of HI: 0.04 atmInitial Pressure of Equilibrium Pressure of Initial Pressure of Equilibrium Pressure of Substituting the values in the formula: So,