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A sample of gas occupies volume of `2.74 dm^(3)` at `0.9` bar and `27^(@)C`. What will be the volume at `0.75` bar and `15^(@)C`? |
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Answer» Form the available data : `V_(1) = 2.74 dm^(3)` , `V_(2) = ?` `P_(1) = 0.9` bar , `P_(2) = 0.75` bar `T_(1) = 27 + 273 = 300 K` , `T_(2) = 15 + 273 = 288 K` According to gas equation, `(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))` or `V_(2) = (P_(1)V_(1)T_(2))/(T_(1)P_(2))` By substituting the values, `V_(2) = ((0.9 "bar") xx (2.74 dm^(3)) xx (288 K))/((300 K) xx (0.75 "bar" )) = 3.16 dm^(3)` |
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