1.

A sample of caustic soda contains 74.6 Na2O by weight. find the purity of the sample

Answer»

Let AMOUNT of Caustic SODA (NaOH) is taken 100g
In 100g of Caustic soda contains 74.6 g of Na₂O .
Let see reaction of Caustic soda :
2NaOH ⇔Na₂O + H₂O
Here it is clear that 2 moles of NaOH form 1 mole of Na₂O
∴ 2(23 + 16 + 1) = 80g of NaOH form (2×23+16) = 62g of Na₂O
∴ 1g of Na₂O = 80/62 g of NaOH
∴ 74.6g of Na₂O = 80/62 × 74.6 = 96.26g

Now , PURITY of Caustic soda = theoretical amount of NaOH/taken amount of NaOH × 100
= 96.26/100 × 100
= 96.26 %


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