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A sample of a radioactive element has a mass of 10 g at an instant t=0. The approximate mass of this element in the sample left after two mean lives is |
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Answer» 1.35 G As `N/N_0=m/m_0=(1/2)^(t//T_(1//2))=(1/2)^(2.88)` `THEREFORE m=m_0(1/2)^(2.88)=10(1/2)^2.88 ` g =10 X 0.1358 g = 1.358 g |
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