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A sample of a gas occupies a volume of 512 mL at `20^(@)C` and `74 cm` of Hg as pressure. What volume would this gas occupy at STP ? |
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Answer» `{:("Initial conditions","Final conditions" (STP),),(P_(1) = 74 cm,P_(2) = 76 cm,),(T_(1) = 20^(@)C = (20 + 273) = 293 K,T_(2) = 0^(@)C = 273 K,),(V_(1) = 512 mL,V_(2) = ?,):}` We know that, `(P_(1)V_(1))/(T_(1)) = (P_(2) V_(2))/(T_(2))` `(74 xx 512)/(293) = (76 xx V_(2))/(273)` So, `V_(2) = (74 xx 512 xx 273)/(293 xx 76)` `= 464.5 mL` |
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