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A sample of 0.50g of an organic compound was treated according to Kjeldahl's method. The ammonia evolved was absorbed in 50ml of 0.5M H_(2)SO_(4). The residual acid required 60mL of 0.5M solution of NaOH for neutralisation. Find the percentage composition of nitrogen in the compound |
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Answer» SOLUTION :Initially taken `H_(2)SO_(4)= 50mL 0.5M` used NaOH = 60 mL 0.5M `:.` unused `H_(2)SO_(4)= 30 mL 0.5M H_(2)SO_(4)` used `H_(2)SO_(4)= (50-30)= 20 mL 0.5 H_(2)SO_(4)` `=40 mL 0.5M NH_(3)` `1000 mL 1M NH_(3)= 17g NH_(3)=14g` nitrogen 40mL 0.5M `NH_(3)=` `=(40 mL XX 0.5M xx 14g)/(1000mL xx 1M)= 0.280` g nitrogen % N `= (0.280 xx 100)/(0.5)= 56` `:.` % of nitrogen = 56% |
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