A sample of 0.1 g of water at 100∘C and normal pressure (1.03×105 Nm−2) requires 54 cal of heat energy to convert to steam at 100∘C. If the volume of the steam produced is 167.1 cc, the change in internal energy of the sample is

A sample of 0.1 g of water at 100∘C and normal pressure (1.03×105 N

1.	A sample of 0.1 g of water at 100∘C and normal pressure (1.03×105 Nm−2) requires 54 cal of heat energy to convert to steam at 100∘C. If the volume of the steam produced is 167.1 cc, the change in internal energy of the sample is
Answer» A sample of $0.1 g$ of water at $100^{\circ} C$ and normal pressure $(1.03 \times 10^{5} {Nm}^{- 2})$ requires $54 cal$ of heat energy to convert to steam at $100^{\circ} C$ . If the volume of the steam produced is $167.1 cc$ , the change in internal energy of the sample is

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A sample of 0.1 g of water at 100∘C and normal pressure (1.03×105 Nm−2) requires 54 cal of heat energy to convert to steam at 100∘C. If the volume of the steam produced is 167.1 cc, the change in internal energy of the sample is

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