1.

A(s)hArrH_(2)S(g)+B(g) At eq., pressure = 18 atm C(s)hArrH_(2)S(g)+D(g) At eq., pressure = 36 atm Calculation mole fraction of B in the mixture.

Answer»

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Solution :`A(s)hArrunderset(x+y x)( H_(2)S(g))+B(g),K_(p_(1))=(9)^(2)=81`
`C(s)hArrunderset(x+y y)(H_(2)S(g))+D(g),K_(p_(2))=(18)^(2)=324`
mole fraction of B in mixture `=x/(2(x+y))`
`=(k_(p_(1)))/(2(K_(p_(1))+K_(p_(2))))`


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