1.

A running man has the same kinetic energy as that of a boy of half his mass. The man speeds up by 2 ms^(-1) and the boy changes his speed by x m s^(-1) so that the kinetic energies of the boy and the man are again equal. Then x in m s^(-1) is

Answer»

1/2 
`2sqrt(2)`
`SQRT(2)`
`2`

SOLUTION :Let the MASS of man be m.
Therefore, mass of the BOY is `m/2`
As. `1/2 mv_1^2 = 1/2(m/2) v_2^2 :. v_1= (v_2)/(sqrt2)`
`1/2 m(v_1 + 2)^2 = 1/2[m/2 (v_2 + X)^2]`
`:. (v_1 + 2)^2 = ((v_2 + x)^2)/(2) " or " v_1 + 2 = (v_2+ x)/(sqrt2)`
But `v_1 = (v_2)/(sqrt2) :. x/(sqrt2) = 2 " or " x = 2sqrt(2)`.


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