Saved Bookmarks
| 1. |
A rope, under tension of `200N` and fixed at both ends, oscialltes in a second harmonic standing wave pattern. The displacement of the rope is given by `y=(0.10)sin ((pix)/(3)) sin (12 pit)`, where `x=0` at one end of the rope, `x` is in metres and `t` is in seconds. Find the length of the rope in metres. |
|
Answer» `y=0.10sin ((pix)/(3))sin (12 pit)` `[M. Bank_(-)S.W._(-)4.60]` `k=(pi)/(3)` `rArr lambda=6m` Length of the rope `=lambda=6m`. |
|