A rod of weight w is supported by two parallel knife edges a and b and is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at a distance x from a. What is the normal reaction on a?

A rod of weight w is supported by two parallel knife edges a and b and

1.	A rod of weight w is supported by two parallel knife edges a and b and is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at a distance x from a. What is the normal reaction on a?
Answer» g forcesN1+N2=WEquating Torques about A Wx=N2d=>N2=Wx/dSo N1=W[1- (x/d)]Normal reaction on A is W[1- (x/d)]And on B is Wx/d

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A rod of weight w is supported by two parallel knife edges a and b and is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at a distance x from a. What is the normal reaction on a?

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