Saved Bookmarks
| 1. |
A rod of negligible heat capacity has length 20cm, area of cross section `1.0cm^(2)` and thermal conductivity `200Wm^(-1)`^(@)C^(-1)` . The temperature of one end is maintained at `0^(@)C` and that of the other end is showly and linearly varied from `0^(@)C` to `60^(@)C` in 10 minutes. Assuming no loss of heat through the sides, find the total heat transmitted through the rod in these 10 minutes. |
|
Answer» Correct Answer - A `(d theta)/(dt)= 60/(10xx60)=0.10^(@)C//sec` `(d theta)/(dt)=(KA)/d(theta_1-theta_2)` `=(KA0.1)/d+(KA0.2)/d+….+(KA60)/d` ltbrge(KA)/d(0.1+0.2+….+60)` `(KA)/d (600/2) (2xx0.1+599xx0.1)` `[a+2a+…na=(n)/(2){2a+(n-1)a}]` `=(200xx1xx10^(-4))/(20xx10^(-2))xx300xx(0.2+59.9)` `=(200xx10^(-2)xx300(60.1))/20` `=3xx10xx60.1` `=1803W=1800W.` |
|