1.

A rod of length L rotates about an axis passing through its centre and normal to its length with an angular velocity omega. If A is the cross section and D is the density of material of rod, its rotational K.E. is :

Answer»

`(1)/(2)AL^(3)DOMEGA^(2)`
`(1)/(6)AL^(3)Domega^(2)`
`(1)/(24)AL^(3)OMEGA^(2)D`
`(1)/(12)AL^(3)Domega^(2)`

Solution :K.E. of rotation
`=(1)/(2)Iomega^(2)=(1)/(2).(ML^(2))/(12).omega^(2)=(1)/(24)XX(ALD)L^(2)omega^(2)`
`=(1)/(24)AL^(3)Domega^(2)`


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