1.

A rod of length 2m and mass 0.5kg is fixed at one end and allowed to hang vertically from a rigid support. Find the work done in raising the other end of the rod until it makes an angle of 60^(@) with the vertical. (g = 10 ms^(-2))

Answer»

SOLUTION :`m= 0.5kg, l= 2M, theta = 60^(@)`
WORD done `W= mg (l)/(2) (1- cos theta)`
`=0.5 xx 10 xx(2)/(2) (1- cos 60^(@))`
`=5 xx (1 - (1)/(2))= 5 xx (1)/(2) = 2.5J`


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