1.

A rod ab is 8 m long and has got a weight of 10 kg at a. The fulcrum is 3 m away from b. Calculate the load at b, if the rod is in balanced condition

Answer»

The length of rod = 8 m .A weight of 10 kg is put at A.Fulcrum is 3 m away from B .LET the weight of load at B be x .Distance of A from fulcrum = 8 m - 3 m                                              = 5 mBy PRINCIPLE of moments :Sum of clockwise moments = sum of anti-clockwise moments .HENCE we can write that :5 m × 10 kg = x × 3 m= > 50 kg m = 3 x m= > 3 x = 50 kg= > x = 50/3 kg= > x = 16.666 kg= > x = 16.67 kgANSWER :The load at B would be 16.67 kg



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