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A ring of redius r is suspended from a point on its circumference. Determine its angular frequency of small oscillations. answer fast

Answer»

ts as PHYSICAL PENDULUM, the time period of which is T = 2π√I/mglHere, I = moment of INERTIA of ring about POINT of suspension= mr^2 + mr^2=2mr^2and l = distance of point of suspension from center of gravity=rnow,T = 2π√2mr^2/mgr=2π√2r/gomega= w = 2π/T (angular frequency )PUTTING the value of T we get,w = √g/2rHappy to help!:)



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