A ring of diameter 0.4 m and of mass 10 kg is rotating about its axis at the rate of 1200 rpm. The angular momentum of the ring is

A ring of diameter 0.4 m and of mass 10 kg is rotating about its axis

1.	A ring of diameter 0.4 m and of mass 10 kg is rotating about its axis at the rate of 1200 rpm. The angular momentum of the ring is
Answer» `60.28 "kgm"^(2) s^(2)` `55.26 "kgm"^(2)s^(2)` `40.28 "kgm"^(2) s^(2)` `50.28 "kgm"^(2)s^(2)` Solution :Here, `r=0.2 m,M=10kgv=1200 "RPM" =20 rps` `L = I omega=(Mr^(2))(2piv)` `=10xx(0.2)^(2)xx2xx(22)/(7)xx20=50.28"kg-m"^(2)s^(-2)`.