1.

A rigid body of mass m is moving in a circle of radius r with constant speed v. The force on the body is mv2/r and is directed towards centre .What is the work done by this force in moving te body over half the circumference of the circle.

Answer»

Work = Force × displacement
Force= mv^2/r
Displacement is the SHORTEST DISTANCE between FINAL and initial point
Shortest distance between the points in HALF circumference is The diameter of circle= 2r
Work=2mv^2



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