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A rightcircular cone and a right circular cylinder have equal base and equal height.If the radius of the base and the height are in the ratio 5 : 12, then theratio of the total surface area of the cylinder to that of the cone is(a) 3 : 1 (b) 13 : 9 (c) 17 : 9 (d) 34 : 9A. `3:1`B. `13:9`C. `17:9`D. `34:9` |
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Answer» Correct Answer - C let the radius of the base are 5k and 12k respectively `:.("Total surface area of the cylinder")/("Total surface area of the cone ")` `=(2pirxxh+2pir^2)/(pirsqrt(r^2+h^2+pir))` `=(2h+2r)/(sqrt(r^2+h^2)+r)+(24k+10k)/(sqrt(25k^2+144k^2)+5k)` `=(34k)/(13k+5k)=(34k)/(18k)=17/9or 17 :9` |
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