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A reversible Carnot's engine is working between 260 K and 300K. It takes 500 cal of heat from sink. Heat rejected to the source at higher temp. for this refrigerator is: |
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Answer» 400 CAL `Q_(2)=500 cal. Q_(1)=?` Here, for refrigerator also `(Q_(1))/(Q_(2))=(T_(1))/(T_(2))` ` Q_(1)=Q_(2)xx(T_(1))/(T_(2))=500 xx (300)/(260)` `Q_(1)=576 cdot 9 cal = 577 cal`. Hence, correct CHOICE is (d). |
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