1.

A reversible Carnot's engine is working between 260 K and 300K. It takes 500 cal of heat from sink. Heat rejected to the source at higher temp. for this refrigerator is:

Answer»

400 CAL
477 cal
377 cal
577 cal.

Solution :`T_(1)=300 K" "T_(2)=260 K.`
`Q_(2)=500 cal. Q_(1)=?`
Here, for refrigerator also `(Q_(1))/(Q_(2))=(T_(1))/(T_(2))`
` Q_(1)=Q_(2)xx(T_(1))/(T_(2))=500 xx (300)/(260)`
`Q_(1)=576 cdot 9 cal = 577 cal`.
Hence, correct CHOICE is (d).


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