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A resistor `R_(1)` dissipates the power `P` when connected to a certain generator. If the resistor `R_(2)` is put in series with `R_(1)`, the power dissipated by `R_(1)`A. DecreasesB. IncreasesC. Remains the sameD. Any of the above depending upon the relative values of `R_(1)` and `R_(2)` |
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Answer» Correct Answer - A (a) Equivalent resistance in the second case` = R_(1) + R_(2) = R` Now, we know that `P prop (1)/(R )` Since in the second case the resistance `(R_(1) + R_(2))` is higher than that in the first case `(R_(1))`. Therefore power dissipation in the second case will be decreased. |
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