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A resistance of `10 Omega` is bent in the from of a closes circle. What is the effective resistance between the two at the ends of any diameter of this circle ?

Answer» Correct Answer - `2.5 Omega`
Each of the two semicircles between the two ends of a diameter has a resistance of `10 Omega//2 = 5 Omega`. These two resistances are in parallel between the two ends of the diameter. Thus, the effective resistance `=5 Omega//2 = 2.5 Omega`.


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