1.

a relation between x and y such that the pt (x y) is eqidistant from the points (7, 1 ) and ( 3, 5 ) ​

Answer»

Answer:

Let P(X,y) be EQUIDISTANT from the POINTS A(7,1) and B(3,5).

AP=BP

AP

2

=BP

2

(x−7)

2

+(y−1)

2

=(x−3)

2

+(y−5)

2

x

2

−14x+49+y

2

−2y+1=x

2

−6x+9+y

2

−10y+25

x−y=2


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