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a regular hexagon of side 10cm has a charge 5 MC at each of its verticle. calculate the potential at the center of the hexagon |
| Answer» N:A REGULAR hexagon of side 10 cm has a charge 5 micro C at each of its vertices. calculate the potential at the center of the hexagon?Answer:The Potential (V) will be 2.7 × 10⁶ VGiven:Side of Hexagon (a) = 10 cm = 0.1 MEACH vertices has charge (q) = 5 μ CExplanation:We know, that the hexagon is made of 6 equilateral triangles. Therefore, OA = OB = ABHence,⇒ OA = OB = 10 cm = 0.1 mAnd, as we know that potential is a scalar quantity, we will be ADDING all the potential acting on the center by scalar addition.Now,Solving,Here, the Charges are same i.e. 5 μC = 5 × 10⁻⁶ C and distance of separation is same i.e. r = 0.1 m.Substituting the values,∴ The Potential (V) will be 2.7 × 10⁶ V. | |