A red car travels 400 m in 20s. A blue car travels 660m in 30s. Which

1.	A red car travels 400 m in 20s. A blue car travels 660m in 30s. Which car has the greater average speed
Answer» ANSWER: BLUE CAR IS FASTER THAN RED CAR. GIVEN: For red car Distance traveled = 400m Time taken = 20 sec For blue car Distance traveled = 660m Time taken = 30 sec TO FIND: Which car has greater speed? ANSWER: Formula $\implies \: average \: speed \: = \frac{total \: distance}{total \: time} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \\ for \: red \: car \\ \: \implies \: average \: speed \: = \frac{400}{20} \\ \implies \: average \: speed \: = 20ms {}^{ - 1} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \\ for \: blue \: car \\ \implies \: average \: speed \: \: = \frac{total \: distance}{total \: time} \\ \implies \: average \: speed \: \: = \frac{660}{30} \\ \implies \: average \: speed \: = 22ms {}^{ - 1}$ BLUE CAR IS FASTER THAN RED CAR NOTE: *some* *IMPORTANT* *FORMULAS* $\implies \: average \: velocity = \frac{total \: displacement}{total \: time} \\ \implies \: average \: speed = \frac{total \: distance}{total \: time}$

A red car travels 400 m in 20s. A blue car travels 660m in 30s. Which car has the greater average speed

Answer»

ANSWER:

BLUE CAR IS FASTER THAN RED CAR.

GIVEN:

For red car

Distance traveled = 400m
Time taken = 20 sec

For blue car

Distance traveled = 660m
Time taken = 30 sec

TO FIND:

Which car has greater speed?

ANSWER:

Formula

$\implies \: average \: speed \: = \frac{total \: distance}{total \: time} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \\ for \: red \: car \\ \: \implies \: average \: speed \: = \frac{400}{20} \\ \implies \: average \: speed \: = 20ms {}^{ - 1} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \\ for \: blue \: car \\ \implies \: average \: speed \: \: = \frac{total \: distance}{total \: time} \\ \implies \: average \: speed \: \: = \frac{660}{30} \\ \implies \: average \: speed \: = 22ms {}^{ - 1}$

BLUE CAR IS FASTER THAN RED CAR

NOTE:

some IMPORTANT FORMULAS

$\implies \: average \: velocity = \frac{total \: displacement}{total \: time} \\ \implies \: average \: speed = \frac{total \: distance}{total \: time}$