a rectangular track is 40m long and 30m broad. a man starts walking fr

1.	a rectangular track is 40m long and 30m broad. a man starts walking from one corner of the track and reaches the opposite corner . find the distance traveled and the magnitude of the displacement.
Answer» $\mathfrak{\large{\underline{\underline{Given:-}}}}$ LENGTH of rectangular track = 40 m Breadth of rectangular track = 30 m $\mathfrak{\large{\underline{\underline{To find :-}}}}$ Distance travelled by man = ? Displacement by man = ? $\mathfrak{\large{\underline{\underline{Solution:-}}}}$ Since, man is started from ONE corner and reaches the opposite corner . Let ABCD be the rectangle given in attachment. AB = DC = 40 m AD = BC = 30 m Let the man start from corner d and move to corner B. Then distance travelled by man = AD + AB = 30 + 40 = 70 m. Displacement of man is given by DIAGONAL of rectangle. Displacement of man = $\bold{DB = \sqrt{ {(DA) }^{2} + {(AB) }^{2} } }$ $\implies$ $\bold{DB= \sqrt{ {30}^{2} + {40}^{2} } }$ $\implies$ $\bold{DB = \sqrt{2500} }$ $\implies$ $\bold{DB = 50 m}$ hence, displacement of man is 50m.