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A rectangular tank is 80 m long and 25 m broad. Water flows into it through a pipe whose cross-section is 25 cm2, at the rate of 16 km per hour. How much the level of the water rise in the tank in 45 minutes. |
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Answer» Given, Dimension of rectangular tank = 80m × 25m = 8000cm × 2500cm Cross section area of pipe = 25 cm2 Rate of flow of water through pipe = 16 km/h Length of pipe = flow of water through it in 45 minute at speed 16 km/h \(=\cfrac{45}{60}\times16\times1000\times100\) cm Volume of pipe = \(=\cfrac{45}{60}\times16\times1000\times100\) cm3 = h = \(\cfrac{16000\times100\times45\times25}{60\times8000\times2500}\) = 1.5 cm |
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