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A rectangular loop of area `20 cm xx 30 cm` is held in a magnetic field of 0.3 T with its plane inclined at (i) `30^(@)` to the field (ii) parallel to the field. Find magnetic flux linked with the coil in each case. |
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Answer» Here, `A = 20 xx 30 cm^(2)` ` = 600 xx 10^(-4) m^(2) = 6 xx 10^(-2) m^(2)` `B = 0.3 T` `theta_(1) = (90^(@) - 30^(@)) = 60^(@) , theta_(2) = 90^(@) - 0^(@) = 90^(@)` `phi_(1) = BA cos theta_(1) = 0.3 xx 6 xx 10^(-2) cos 60^(@)` `= 0.9 xx 10^(-2)Wb` `phi_(2) = BA cos theta_(2) = 0.3 xx 6 xx 10^(-2) cos 90^(@) = Zero` |
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