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A rectangular loop is being pulled at a constant speed `v`, through a region of certain thickness `d`, in which a uniform magnetic field `B` is set up. The graph between position `x` of the right hand edge of the loop and the induced e.m.f. `E` will be B. C. D. |
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Answer» Correct Answer - B As `x` increase so `(dB)/(dt)` increase i.e., induced emf (e) is negative. When loop completely entered in the magnetic field, emf=0 when it exit out `x` increase but `(dB)/(dt)` decrease i.e., `e` is positive. |
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