A rectangular lawn of 24 x 36 m2 has tworoads each 4m wide running bet

1.	A rectangular lawn of 24 x 36 m2 has tworoads each 4m wide running between thepark. One is parallel to length and other isparallel to width. Cost of gravelling is 25paise/m2. Find the total cost ofgravelling?IRs. 84Rs. 64ח
Answer» Given: The length of the RECTANGULAR lawn is 36m And the breadth of the rectangular lawn is 24m Also, Given that two roads each 4m WIDE running between the park. One is parallel to the length and the other is parallel to the width. So, see the attached image. ABCD is a rectangular lawn. GHKL and EFIL are the two roads running between the park, parallel to width, and length respectively. So, In GHKL Length = 24m and breadth = 4m Area = lb = 24 × 4 = 96m² And, In EFIL Length = 36m and breadth = 4m Area = lb = 36 × 4 = 144m² There is square MNOP Area = side² = 4² = 16m² So, Now adding both and subtracting the area of the square = 96 + 144 - 16 = 240 - 16 = 224 m² So, we get the are of the two roads Now, COST of graveling PER m² = 25 paise So, For 224m² = 224 × 25 = 5600 paise So, 5600 ÷ 100 = Rs.56 Hence The cost will be Rs. 56

A rectangular lawn of 24 x 36 m2 has tworoads each 4m wide running between thepark. One is parallel to length and other isparallel to width. Cost of gravelling is 25paise/m2. Find the total cost ofgravelling?IRs. 84Rs. 64ח

Answer»

Given:

The length of the RECTANGULAR lawn is 36m

And the breadth of the rectangular lawn is 24m

Also,

Given that two roads each 4m WIDE running between the park. One is parallel to the length and the other is parallel to the width.

So, see the attached image.

ABCD is a rectangular lawn.

GHKL and EFIL are the two roads running between the park, parallel to width, and length respectively.

So,

In GHKL

Length = 24m and breadth = 4m

Area = lb = 24 × 4 = 96m²

And,

In EFIL

Length = 36m and breadth = 4m

Area = lb = 36 × 4 = 144m²

There is square MNOP

Area = side² = 4² = 16m²

So,

Now adding both and subtracting the area of the square

= 96 + 144 - 16

= 240 - 16

= 224 m²

So, we get the are of the two roads

Now,

COST of graveling PER m² = 25 paise

So,

For 224m²

= 224 × 25

= 5600 paise

So,

5600 ÷ 100 = Rs.56

Hence

The cost will be Rs. 56