QUESTION:

A rectangular FIELD is 28 m long and 18 m wide. How many triangular flower beds each of base 7 m and altitude 6 m can be laid on the field?

Answer:

Step-by-step explanation:

• Length of rectangular field = 28 m
• Width/Breadth of the rectangular field = 18 m
• Base of the triangular flower bed = 7 m
• Altitude of the triangular flower bed = 6 m

• The number of triangular flower beds that can be laid on the rectangular field

➔ Here we have to find how many triangular flower beds can be laid on the rectangular field.

➔ First finding the area of the rectangular field,

➔ Area of a rectangle is given by,

    Area of a rectangle = l × b

    where l is the length

    and b is the breadth

➔ Substitute the data,

    Area of the rectangular field = 28 × 18

    Area of the rectangular field = 504 m²

➔ Hence area of the rectangular field is 504 m².

➔ Now finding the area of the triangular flower bed,

➔ Area of a triangle id given by,

    Area of a triangle = 1/2 × b × h

    where b is the base of the triangle

    h is the height or the altitude

➔ Substitute the data,

    Area of the triangular flower bed = 1/2 × 7 × 6

    Area of the triangular flower bed = 7 × 3

    Area of the triangular flower bed = 21 m²

➔ Hence area of the flower bed is 21 m².

➔ Now finding the number of flower beds,

   Number of flower beds = Area of field/Area of flower bed

➔ Substitute the data,

    Number of flower beds = 504/21

   Number of flower beds = 24

➔ Hence 24 flower beds can be laid on the rectangular field.