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A rectangular block has dimensions 5 cm xx5 cm xx 10 cm. Calculate the resistance measured between (a) two square ends and (b) the opposite rectanglar ends specific resistance of the material is 3.5xx10^(-5) Omega m |
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Answer» Solution :a) Resistance between two square ENDS `R_(1)=(rhol)/(A)rArr R_(1)=(3.5xx10^(-5)xx10xx10^(-2))/(5xx5xx10^(-4))` `=1.4xx10^(-3)Omega`  B) Resistance between the opposite rectangular ends `R_(2)=(rhol)/(A)rArr R_(2)=(3.5xx10^(-5)xx5xx10^(-2))/(5xx10xx10^(-4))=3.5xx10^(-4)Omega` |
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