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A rectangle with diagonal of length 20cm has sides in the ratio 2:1 find the area of the rectangle. |
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Answer» Answer: le the SIDES of rectangle be AB&CD=LENGTH=2x & BC&AC=bradth=X DIAGONAL is AD=20cm By Pythagoras theorem (AD)^2=(AB)^2 + (BC)^2 = (2x)^2+(x)^2 =4x^2+x^2 =5x^2 (20)^2=5x^2 20=5x x=20/5 x=4 one SIDE =x=4cm other side=2x=2×4=8cm Area of rectangle= length ×breadth =8×4 =32cm^2 |
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