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A real image, 1/5th the size of the object, is formed at a distance of 18 cm from amirror. What is the nature of the mirror? Calculate its focal length. |
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Answer» e is your answer if you love me answer please don't forget to meet me BRAINLIEST and you follow meAs the image is real the mirror has to be CONCAVE. Let its focal length be f. u and v both have to be negative according to the COORDINATE system sign CONVENTION. Also MOD(v) = (1/5)*mod(u). We have As the image is real the mirror has to be concave. Let its focal length be f. u and v both have to be negative according to the coordinate system sign convention. Also mod(v) = (1/5)*mod(u). We have 1/v + 1/u = 1/f or As the image is real the mirror has to be concave. Let its focal length be f. u and v both have to be negative according to the coordinate system sign convention. Also mod(v) = (1/5)*mod(u). We have 1/v + 1/u = 1/f or = -1/18 -1/(5*18) = -6/90 = 1/f or f = -15 cm |
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