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(A) Read the Passage and answer the following questions. [10 Marks)Finding food in winter is Difficult for most animals when various sources of food likeinsects or plants are not available in plenty. It is during this time, most animals cope with thelack of food by hibernatingHibernation is that deep sleep taken by certain animals that helps them not to waste energythat they can survive the winter without much food. An Animal's body temperature falls duringhibernation. The heartbeat and breathing slows down so it saves energyHibernating animals prepare for winter by eating more food than need. They store food asbody fat. This fat is used as energy when they sleep. The fat is formed in patches near theTITIAN DUTEανανv ovou versy WAITII UITVOV viganswhen they wake up. Fish, turtles, bear, frogs and lizards are the example of hibernating animals.Questions :1. How do animals deal with the lack of food during winter?2. How do hibernating animals prepare for winters?3. How is the fat used in sleep?4. Name four hibernating animals.5. Give a Suitable title to this passage.(B) Write a story from the points given below and give a suitable Title to story.[10 MarksRanesh and Raj are two friends - Ranesh had servant named Raju - Raj hadservant named Shambhu - Both servant foolish - Two friends debate - Who is morefoolish - Ramu or Shambhu? - Decided to give a test - Both were told to go homeand check Ranesh and Raj were at home or not - Ramu and Shambhu returns - Ramucomplains - Waste of time.Q. 4 (A) Write an article about 'Planting a Tree'.110 Marks)(B) Write a letter to the Principal of your school asking permission for leavedue to high fever.[10 Marks)​

Answer»

<P>Answer:

principal => ₹15000

time. => 1 year

rate of INTEREST => 8% p.a.

simple interest => p × r × t / 100

=> 15000 × 1 × 8 / 100

=> 1200

\tt\pink{interest\: for \: first \: year}interestforfirstyear

=> ₹1200

so , AMOUNT => p + s.i.

=> ₹15000 + ₹1200

₹16200

\huge\mathfrak\red{second \: year}secondyear

in second year, the amount in the first year become the principal here ,

so we have, => principal => ₹ 16200

time => 1 year

rate of interest => 8% p.a.

simple interest => 16200 × 1 × 8 / 100

=> ₹ 1296

so compound interest for two years => ₹1200 + ₹1296 =

₹2496



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