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A reactor is supplied with 6 moles of N2 and 9 moles of H2, if 3 moles of NH3 is produced, how many moles of H2 are left at the end?(a) 1.5(b) 3(c) 4.5(d) 6 |
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Answer» The correct option is (c) 4.5 Easy explanation: The reaction is N2 + 3H2 -> 2NH3, => extent of reaction = (3 – 0)/2 = 1.5, => moles of H2 left = 9 – 1.5*3 = 4.5. |
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