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A reactor is supplied with 10 moles glucose and excess oxygen to produce 40% CO2, 60% H2O, what is the rate of products?(a) 25 mole(b) 50 mole(c) 75 mole(d) 100 mole

Answer» Correct answer is (a) 25 mole

Explanation: The reaction is C6H12O6 + 6O2 -> 6CO2 + 6H2O, Let the rate of products be P. Element balances, C: 10(6) = 6*0.4P(1), => P = 25 mole.


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