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A reaction rate contant doubles between 300 and 310 k. By which of the following factors does the rate constant increases between 400-410 K. |
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Answer» 3.39 `"log"("log"(k_(2))/(k_(1)))/("log"(k_(2))/(k_(1)))=(10)/(400xx410)*(300xx310)/(10)` `K'_(2)` and `k'_(1)` are rate constant at 410 and 400 K respectively. `k_(2)` and `k_(1)` are rate constant at 310 and 300 K respectively .Here `k_(2).k_(1)=2` `therefore "log"(k_(2)')/(k_(1)')=(3xx31)/(4xx41)xx"log"2` `=(3xx31xx0.3010)/(4xx41)=0.1707` `(k_(2))/(k_(1))`=antilog 0.1707 =1.48 |
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