1.

A reaction rate contant doubles between 300 and 310 k. By which of the following factors does the rate constant increases between 400-410 K.

Answer»

3.39
2
1.48
1.1

Solution :For any reaction , the value of RATE CONSTANT DOUBLES between 300 and 310 . For any other temp the rate constant decrease
`"log"("log"(k_(2))/(k_(1)))/("log"(k_(2))/(k_(1)))=(10)/(400xx410)*(300xx310)/(10)`
`K'_(2)` and `k'_(1)` are rate constant at 410 and 400 K respectively. `k_(2)` and `k_(1)` are rate constant at 310 and 300 K respectively .Here `k_(2).k_(1)=2`
`therefore "log"(k_(2)')/(k_(1)')=(3xx31)/(4xx41)xx"log"2`
`=(3xx31xx0.3010)/(4xx41)=0.1707`
`(k_(2))/(k_(1))`=antilog 0.1707 =1.48


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