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A ray of light is incident at 60∘ on glass-air interface. Find out the total deviation of the ray? \({\mu}_{g}\) = √2, \({\mu}_{a}\) = 1 |
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Answer» A ray of light is incident at 60∘ on glass-air interface. Find out the total deviation of the ray? \({\mu}_{g}\) = √2, \({\mu}_{a}\) = 1 |
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