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A ray of light is incident at 60∘ on glass-air interface. Find out the total deviation of the ray? \({​\mu}_{g}\) = √2, \({​\mu}_{a}\) = 1

Answer»

A ray of light is incident at 60 on glass-air interface. Find out the total deviation of the ray?

\({​\mu}_{g}\) = 2, \({​\mu}_{a}\) = 1




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